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kati45 [8]
3 years ago
12

Find all the whole values of a for which the solution of the equation ax = 6 is a whole number.

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

<em>1, 2, 3, 6</em>

Step-by-step explanation:

The given equation is,

\Rightarrow ax = 6

\Rightarrow x = \dfrac{6}{a}

We need to to find all the whole values of a for which the solution of the equation i.e x will be a whole number.

We know that when a number is divided by one of its factor it leaves a remainder of 0 or the result we get is a whole number.

That is why, we need a as one of the factors of 6, i.e 1, 2, 3, 6 in order to get x as a whole number.

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Jasmine needs to make a bouquet of 24 yellow and orange carnations. The ratio of yellow carnations to all of the carnations must
aleksley [76]

Answer:

3

Step-by-step explanation:

just did it

4 0
3 years ago
Simplify 6 - 3(4 - 3x)<br> -3x - 6<br> 9x + 18<br> 9x - 6
svet-max [94.6K]

Answer:

6 (19 x - 2)

Step-by-step explanation:

Simplify the following:

6 - 3 (4 - 3 x) - 3 x - 6×9 x + 18×9 x - 6

-6×9 = -54:

6 - 3 (4 - 3 x) - 3 x + -54 x + 18×9 x - 6

18×9 = 162:

6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6

Grouping like terms, 6 - 3 (4 - 3 x) - 3 x - 54 x + 162 x - 6 = (-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6):

(-3 x - 54 x + 162 x) - 3 (4 - 3 x) + (6 - 6)

-3 x - 54 x + 162 x = 105 x:

105 x - 3 (4 - 3 x) + (6 - 6)

6 - 6 = 0:

105 x - 3 (4 - 3 x)

-3 (4 - 3 x) = 9 x - 12:

9 x - 12 + 105 x

Grouping like terms, 105 x + 9 x - 12 = (105 x + 9 x) - 12:

(105 x + 9 x) - 12

105 x + 9 x = 114 x:

114 x - 12

Factor 6 out of 114 x - 12:

Answer: 6 (19 x - 2)

7 0
3 years ago
Given m parallel to n, find the value of x, (7x+14) and (9x-8)
iVinArrow [24]

Answer:

x=11

Step-by-step explanation:

(7x+14)=(9x-8)

7x-9x=-14-8

-2x=-22

-2x/-2=-22/-2

x=11

8 0
2 years ago
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Ksju [112]
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see what that gives you
8 0
3 years ago
Which algebraic expression means “three more than a number squared”?
rodikova [14]
3 more then a number squared......

n^2 + 3
5 0
3 years ago
Read 2 more answers
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