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Llana [10]
2 years ago
5

Help please I will mark brainlest

Mathematics
2 answers:
Effectus [21]2 years ago
8 0

Answer:

they need brainliest :)

rodikova [14]2 years ago
7 0

Answer:

5\sqrt{7}

Step-by-step explanation:

\frac{30\sqrt{14} }{6\sqrt{2} }

Cancel out 6 in both numerator and denominator.

\frac{5\sqrt{14} }{\sqrt{2} } Rationalize the denominator of \frac{5\sqrt{14} }{\sqrt{2} } by multiplying the numerator and denominator by \sqrt{2}.

\frac{5\sqrt{14}\sqrt{2}  }{(\sqrt{2})^{2}  }

The square of  \sqrt{2} is 2

Factor 14=2 × 7. Rewrite the square root of the product \sqrt{2x7} as the product of square roots \sqrt{2}\sqrt{7}.

\frac{5\sqrt{2}\sqrt{7}\sqrt{2}   }{2}

Multiply \sqrt{2} and \sqrt{2} to get 2.

\frac{5x2\sqrt{7} }{2}

Cancel out 2 and 2.

5\sqrt{7}

Hope it helps and have a great day! =D

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Answer:

12.25\pi sq m

Step-by-step explanation:

if circumference is 7\pi then the diameter is 7

Area = \pir²

A = (3.5)²\pi

A = 12.25\pi

7 0
2 years ago
What is the equation of a circle whose center is (2,0) and has a radius= 9?
Flauer [41]
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Your equation is:
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Is this a real question

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Angela took a general aptitude test and scored in the 83rd percentile for aptitude in accounting.
tigry1 [53]

Answer:

(a) 83% of the scores were at or below her score.

(b) 17% was above her score.

Step-by-step explanation:

Given that:

Percentile score of Angela in the general aptitude test = 83rd percentile

To find:

a) Percentage of scores which were at or below her score?

b) Percentage of score which were above her score?

Solution:

First of all, let us learn about the term "<em>Percentile</em>"

Percentile is the value below which the certain percent of people/marks fall.

Therefore, when we say percentile of someone's score is x, then there are x\% of scores are at the same level or below.

And (100-x)\% of the scores are above this level.

Therefore, we can say that:

83% of the scores were at the same level or below the score of Angela.

And (100-83)\% = 17\% of the scores were above the score of Angela.

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