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3 years ago

15

Jackson’s mom is 44, which is four times as old as Jackson. Write an equation that can be used to find Jackson’s age. Then, solv

e the equation to find Jackson’s age. Show your work!

2 answers:

77julia77 [94]3 years ago

7 0

Answer: he is 11 years old

Step-by-step explanation: 44 divided by 4 = 11

Mumz [18]3 years ago

7 0

Answer 44 divided by 4 (11)

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Solve this equation. 25) v - 6(4v + 6) = -82

grin007 [14]

Answer:

$v = 2$

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

$v + -24v + -36 = -82$

Combine 'like' terms:

$(v -24v) + (-36) = -82$

$-23v - 36 = -82$

Next, you'll want to add 36 to both sides of the equation.

$-23v-36 + 36 = -82 + 36$

$-23v = -46$

Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

$v = 2$

I hope this helped you! Leave a comment below if you have any further questions! :)

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3 years ago

40% de cuanto son 32?

OlgaM077 [116]

Do not speak Spanish

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4 years ago

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at silver gym membrship is 25$ per month and personal training sessions are thirty dollars each.At fit factor membership is 65$

NARA [144]

25+30x=65+20x
30x=40+20x
10x=40
x=40/10
x=4

x is for the number of sessions

ANSWER: 4 sessions
It will cost 145$ for both gyms after 4 sessions.

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3 years ago

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The Columbia Tower in Seattle is 954 feet tall. The Seafirst Tower is T feet tall and d feet away from the Colombia Tower. Find

Blababa [14]

You have to include a drawing that relates the distace between de towers and some angles.

I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.

This lets you calculate the distance between the towers, d, as

tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft

The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.

Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft

Answer: 366.29 ft

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3 years ago

Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end

zalisa [80]

we know that

$4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}$

$6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}$

To find how long are $6\frac{1}{2}$ sections placed end to end

Multiply the number of sections by the length of one section

so

$\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft$

$\frac{169}{6}\ ft =28\frac{1}{6}\ ft$

therefore

<u>the answer is</u>

$28\frac{1}{6} \ ft$

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4 years ago

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