Y=(1/2)x^2 + 2x - 1
3x - y = 1, or y=3x-1
substitute
3x-1=(1/2)x^2+2x-1
0=(1/2)x^2-x
0=x(0.5x-1)
x=0,2
y=2+4-1=5
3(2)-1=5.
When x=2 y=5 (2,5) is one solution
when x=0, y=-1, (0,-1) is the other solution
n has a negative exponent, so you need to rewrite the expression using the negative exponent rule b^-n = 1/b^n
(m^8 1/n^4)^1/4
Now make m^8 a fraction buy giving it a denominator of 1:
(m^8 / 1 1/n^4)^1/4
Multiply the fractions together to get m^8/n^4
Now divide the exponents by 4 to get the final answer of:
m^2/n
The cube root of 81 is 4.32674871092
Answer:
A(n+1)=A(n)+3, for n>=0 and A(1)=5
Step-by-step explanation:
This sequence can be expressed in a recursive form. A recursive formula is one where each term can be expressed as a function of its preceding terms. For example; term 5 precedes 8, 8 precedes 11, 11 precedes 14, and 14 precedes 17.
The terms can be expressed as follows;
A(n+1)=A(n)+3, for n>=0 and A(1)=5
where;
A(1): First term
n: nth term
A(n): current term
A(n+1): Next term
d=3: common difference
Since in order to get the next term, one has to add 3 to the preceding term, therefor 3 is the common difference between A(n+1) and A(n)+3
Therefor;
A(n+1)=A(n)+3, for n>=0 and A(1)=5
Answer:
this is brainly and i dunno if this would count as a brainly question
XOXOXOXXO Mashayla
Step-by-step explanation: