The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³
and that's exactly the same as
( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres
is the cube of the ratio of their radii.
Earth radius = 6,371 km
Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note:
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.
Rhombuses have acute and obtuse angles, so if it gives one just subtract it from 180
So,
The standard form is:
y = mx + b
First, we find "m," the slope. Subtract the y-coordinates from each other. Do likewise with the x-coordinates.
2 - -3 = 5
2 - 0 = 2
Slope = 5/2
Now, we can substitute the second solution into this equation for x and y and solve for "b."
Now we have our complete equation.
Answer:
IRREGULAR TERM OF FRACTIONS
Step-by-step explanation:
2 1/3
= 7/3 ANSWER
