Can u please help me

2. Sandi can run for one hour at a constant speed of 348 cm per second. Marci can run for one

Zanzabum

Answer:

Marci is the faster runner.

Step-by-step explanation:

Sandi can run 348 cm in a second. Let's find out how many cm she can run in a minute: in a minute there are 60 seconds. So lets multiply 348cm times 60, this gives you 20,880. That is how much she travels in a minute, now let's find out how much she runs in an hour: if she runs 20,880 cm in an minute and there are 60 minutes in an hour, then all you have to do is multiply 20,880 times 60, this gives you 1,252,800. That is how many cm she runs in an hour. Now let's change from cm to miles. There are 160,934 cm in a mile. If we divide 1,252,800 by 160,934 this will give you

7 0

1 year ago

The expression 3xy+12y-5x+7w has how many terms in polynomial ??

bulgar [2K]

Answer:

4

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago

Negative vectors

Lilit [14]

First you write what the vectors are, then you subtract z from w by subtracting their corresponding values <-4-3,1-4>= <-7,-3>, then to get subtracting the next answer you subtract w from z which is <3--4,4-1> = <7,3>