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3 years ago

3. The student council is selling roses to collect funds for a charity. The graph be

Mathematics

1 answer:

dexar [7]3 years ago

5 0

Answer:

$Unit = 3$

Step-by-step explanation:

Given

See attachment for graph

Required

The unit cost

Pick any point on the dots of the graph; we have:

$(x,y) = (2,6)$

The unit cost is then calculated as:

$Unit = \frac{6}{2}$

$Unit = 3$

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The sales tax in one state is 6 percent, Write a function rule for finding the total cost for an item with selling price x, then

Debora [2.8K]

Sales tax = 6% or 6/100.
assuming tax is added onto the item:
total cost function f(x) = price + tax
however, assuming the cost price = sales price - tax, then:
f(x) = sales price - tax
This is not really a business or accounting forum, its a maths forum, so you need to be clearer about business or accounting terms such as total cost, selling price, selling cost.

3 0

3 years ago

Hi!! I need some help with those exercises can anybody help me please !! Thanks you

elena55 [62]

Answer:

Step-by-step explanation:

(a+b)^2=a^(2)+2ab+b^(2)

(a-b)^2=a^(2)-2ab+b^(2)

13)

(x+2)^(2)-(x-1)^2

x^(2)+4x+4-(x^(2)-2x+1)

x^(2)+4x+4-x^(2)+2x-1

6x+3

15)

(x+5)^(2)-(x+1)^2

x^(2)+10x+25-(x^(2)+2x+1)

x^(2)+10x+25-x^(2)-2x-1

8x+24

6 0

3 years ago

Multiply. Write the product as one power. a to the 8th power x a to the 5th power.

Hatshy [7]

$\bf a^8\cdot a^5\impliedby \textit{same base \underline{a}, add the exponents}\implies a^{8+5}\implies a^{13}$

6 0

3 years ago

What are the zeros of the function below? F(x)= (x-1)(x+1)/6(x-4)(x+7)

Lisa [10]

Answer:

+1 and -1

Step-by-step explanation:

The function in this problem is:

$f(x)=\frac{(x-1)(x+1)}{6(x-4)(x+7)}$

First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.

In order to find the domain, we have to require that the denominator is different from zero, so

$6(x-4)(x+7)\neq 0$

which means:

$x\neq 4\\x\neq -7$

So the domain is all values of x, except from 4 and -7.

Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:

$(x-1)(x+1)=0$

This is verified if either one of the two factors is equal to zero, therefore:

$x-1=0\\\rightarrow x=+1$

and

$x+1 = 0\\\rightarrow x=-1$

We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.

7 0

3 years ago

Can you show me how to do Thisss.

frez [133]

$x=0.\overline{3}\\
10x=3.\overline{3}\\
10x-x=3.\overline{3}-0.\overline{3}\\
9x=3\\
x=\dfrac{3}{9}=\dfrac{1}{3}\\\\
x=-0.\overline{2}\\
10x=-2.\overline{2}\\
10x-x=-2.\overline{2}-(-0.\overline{2})\\
9x=-2.\overline{2}+0.\overline{2}\\
9x=-2\\
x=-\dfrac{2}{9}\\\\
x=1.\overline{7}\\
10x=17.\overline{7}\\
10x-x=17.\overline{7}-1.\overline{7}\\
9x=16\\
x=\dfrac{16}{9}=1\dfrac{7}{9}$

$x=-2.\overline{6}\\
10x=-26.\overline{6}\\
10x-x=-26.\overline{6}-(-2.\overline{6})\\
9x=-26.\overline{6}+2.\overline{6}\\
9x=-24\\
x=-\dfrac{24}{9}=-2\dfrac{2}{3}\\\\
x=0.4\overline{6}\\
10x=4.\overline{6}\\
100x=46.\overline{6}\\
100x-10x=46.\overline{6}-4.\overline{6}\\
90x=42\\
x=\dfrac{42}{90}=\dfrac{7}{15}$

$x=-1.8\overline{3}\\
10x=-18.\overline{3}\\
100x=-183.\overline{3}\\
100x-10x=-183.\overline{3}-(-18.\overline{3})\\
90x=-183.\overline{3}+18.\overline{3}\\
90x=-165\\
x=-\dfrac{165}{90}=-1\dfrac{5}{6}$

8 0

3 years ago