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DanielleElmas [232]
3 years ago
8

Write 45.21% as a decimal

Mathematics
2 answers:
Leona [35]3 years ago
8 0

Answer:

.4521

Step-by-step explanation:

when converting a percentage to a decimal you have to move the decimal point over two times to the left. do if you have 100% you moved the decimal point over two and get 1.00

kodGreya [7K]3 years ago
6 0

Answer:

0.4521

Step-by-step explanation:

Instead, you can simply multiply a number by 45.21 as a decimal to get the answer.

45.21 percent means 45.21 per hundred. Therefore, to get 45.21 as a decimal, all you have to do is divide 45.21 by 100 like so:

45.21 ÷ 100 = 0.4521

Shortcut: When you divide anything by 100, just move the decimal point two places to the left.

Normally, to calculate 45.21 percent, you would multiply a number by 45.21 percent and then you would take the product of that and divide it by 100 to get the answer.

(hope this helps can i plz have brainlist :D hehe)

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3 years ago
Students conducted a study of different sized containers and found that the box shown held 240 blocks. What is the empirical rat
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Answer:

  B.  2 blocks per cubic inch

Step-by-step explanation:

The volume in cubic inches is the product of the dimensions in inches. The ratio of blocks per cubic inch is found by dividing the number blocks by the number of cubic inches. (Effectively, "per" means "divided by".)

  (240 blocks)/((6 in)(4 in)(5 in)) = 240/120 blocks/in³ = 2 blocks/in³

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Proportional or non-proportional ​
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Proportional

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3 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
How to graph equations like y=-x -12
maria [59]
To graph equations like y = -x -12
Since this is in slope intercept form we are automatically given the y-intercept which in this case is -12 so (0,-12)
the coefficient in front of the x is the slope, in this case it is -x so that means -1/1 or -1
To graph this you would plot a point at the y-intercept, then down one over one (negative slope means down instead of up) then to the right, however long to create a line

Hope this helps :)<span />
7 0
3 years ago
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