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ExtremeBDS [4]
3 years ago
5

Which expression is equivalent to

Mathematics
1 answer:
NISA [10]3 years ago
4 0

Answer:

\sqrt{128x^8y^3} = 8 x^4 y \sqrt{2y}

Step-by-step explanation:

Given

\sqrt{128x^8y^3} --- the complete expression

Required

The equivalent expression

We have:

\sqrt{128x^8y^3}

Expand

\sqrt{128x^8y^3} = \sqrt{128* x^8 * y^3}

Further expand

\sqrt{128x^8y^3} = \sqrt{64 * 2* x^8 * y^2 * y}

Rewrite as:

\sqrt{128x^8y^3} = \sqrt{64 * x^8 * y^2* 2 * y}

Split

\sqrt{128x^8y^3} = \sqrt{64 * x^8 * y^2} * \sqrt{2 * y}

Express as:

\sqrt{128x^8y^3} = (64 * x^8 * y^2)^\frac{1}{2} * \sqrt{2y}

Remove bracket

\sqrt{128x^8y^3} = (64)^\frac{1}{2} * (x^8)^\frac{1}{2} * (y^2)^\frac{1}{2} * \sqrt{2y}

\sqrt{128x^8y^3} = 8 * x^\frac{8}{2} * y^\frac{2}{2} * \sqrt{2y}

\sqrt{128x^8y^3} = 8 * x^4 * y * \sqrt{2y}

\sqrt{128x^8y^3} = 8 x^4 y \sqrt{2y}

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Answer:

Option 4

Step-by-step explanation:

Trying the first 2 pairs and confirm  the Last Option

y=5*2^x

5 0
3 years ago
Suppose a simple random sample of size nequals49 is obtained from a population with mu equals 78 and sigma equals 28.
VLD [36.1K]

Answer:

0.0735,0.0179,0.7026

Step-by-step explanation:

Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.

Sample size = 49

Population mean = 78

Population std deviation = 28

Std error of sample mean = \frac{\sigma}{\sqrt{n} } \\=4

a) \bar x: N(78, 4)

b) P(\bar x >83.8)\\=0.0735

(by converting to Z and finding value from Z table)

c) P (x overbar less than or equals 69.6 )​

=P(\bar x \leq 69.6)\\=0.0179

d) P (75.8 less than x overbar less than 88 )

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4 0
4 years ago
Solve. 15 − 6(x + 1) = 12<br> Help nowwwww
Gekata [30.6K]

Answer:

Your answer would be 2

Step-by-step explanation:

15 - 6(x+1) =12

15- 6*x +6*1 = 12

15 - 6x + 6 = 12

15 - 6 + 6x = 12

9 + 6x = 12

9 - 9 + 6x = 12 - 9

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5 0
4 years ago
Is this question two step or one step?
Schach [20]
Which question do you need to know about
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4 years ago
Find the product of (5t-3) and (3t +7) when t = 6
emmasim [6.3K]

Answer:

675

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

(5t - 3) · (3t + 7)

t = 6

<u>Step 2: Evaluate</u>

  1. Substitute in <em>t</em>:                    (5(6) - 3) · (3(6) + 7)
  2. (Parenthesis) Multiply:       (30 - 3) · (18 + 7)
  3. (Parenthesis) Subtract:      27 · (18 + 7)
  4. (Parenthesis) Add:             27 · 25
  5. Multiply:                              675
8 0
3 years ago
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