Answer:
h(1.5) = 7.3 ft
h(10.3) = 24.9 ft
Step-by-step explanation:
Given the function h(d) = 2d + 4.3,
where:
h = height of the water in a fountain (in feet)
d = diameter of the pipe carrying the water (in inches)
<h3>h(1.5)</h3>
Substitute the input value of d = 1.5, into the function:
h(1.5) = 2(1.5) + 4.3
h(1.5) = 3 + 4.3
h(1.5) = 7 feet
The height of the water in a fountain is 7 feet when the diameter of the pipe is 1.5 inches.
<h3>h(10.3)</h3>
Substitute the input value of d = 10.3, into the function:
h(10.3) = 2(10.3) + 4.3
h(10.3) = 20.6 + 4.3
h(10.3) = 24.9 feet
The height of the water in a fountain is 24.9 feet when the diameter of the pipe is 10.3 inches.
<h3>Context of the solutions to h(1.5) and h(10.3):</h3>
The solutions to both functions show the relationship between the diameter of the pipe to the height of the water in a fountain. The height of the water in fountain increases relative to the diameter of the pipe. In other words, as the diameter or the size of the pipe increases or widens, the height of the water in a fountain also increases.
Collinear=On the same line
N-U
N-T
U-T
I believe that is what this questions is asking. :)
Answer:
3(x+2)
Step-by-step explanation:
Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank
boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time
boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet
The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates
(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x
1100x + x^2 = 1400x + 700000
x^2-300x -700000 = 0 quadratic formula yields x = 1000
One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m
Answer:
Ms, Erickson added 6x^3 plus -3x^2 and these terms have different exponents.l
Step-by-step explanation:
