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Usimov [2.4K]
3 years ago
5

Daniela painted a photo that was 4/5 afoot by 1 7/8 of afoot. What was the area?​

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

\frac{3}{2} square feet

Step-by-step explanation:

The dimensions of the photo is 4/5 by 1 7/8 of a foot.

But,

1 7/8 = \frac{15}{8} feet

So that,

length of the photo = \frac{15}{8} feet

width of the photo = \frac{4}{5} feet

The area of the photo = length x width

                                     = \frac{15}{8} x \frac{4}{5}

                                     = \frac{60}{40}

                                     = \frac{3}{2}

Area of the painted photo is \frac{3}{2} square feet.

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