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3 years ago

Daniela painted a photo that was 4/5 afoot by 1 7/8 of afoot. What was the area?

Mathematics

1 answer:

Ahat [919]3 years ago

8 0

Answer:

$\frac{3}{2}$ square feet

Step-by-step explanation:

The dimensions of the photo is 4/5 by 1 7/8 of a foot.

But,

1 7/8 = $\frac{15}{8}$ feet

So that,

length of the photo = $\frac{15}{8}$ feet

width of the photo = $\frac{4}{5}$ feet

The area of the photo = length x width

= $\frac{15}{8}$ x $\frac{4}{5}$

= $\frac{60}{40}$

= $\frac{3}{2}$

Area of the painted photo is $\frac{3}{2}$ square feet.

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Solve for x.<br> 8.7 + X = 7<br> =<br> 1.1<br> x = [?]

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Daniela painted a photo that was 4/5 afoot by 1 7/8 of afoot. What was the area?​

Daniela painted a photo that was 4/5 afoot by 1 7/8 of afoot. What was the area?