Answer: This problem statement does not provide a useful issue statement.
Answer:
<u> A. It uses binary numbers in its algorithm</u>
Explanation:
A Binary search is a type of algorithm designed to look through <em>only </em>a sorted array of data for a particular item.
It is<em> more efficient (faster) </em>than sequential search since the algorithm doesn't have to look up the entire array of data, but simply repeatedly divide in half the section of the array that could contain the searched item.
Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Hi!
The answer is C. Double replacement.
Have a nice day!
Answer:
I would say D hope this helps