I believe it’s g(k)=(-k- 3)(-k+3)
Answer:
1.25cm
Step-by-step explanation:
<em>Complete question:</em>
The prism has a volume of 35 cm cubed workout h, the height of the triangular cross section
<em>length=7cm</em>
<em>width = 4cm</em>
<em></em>
The volume of the prism is expressed as;
Volume = Base Area * Height
Given
Volume of the prism = 35cm^3
Base Area = length * width
Base Area = 7cm * 4cm
Base Area = 28cm^2
Substitute the given values into the formula
35 = 28* Height
Cross multiply
35 = 28 * Height
35 = 28 Height
Height = 35/28
Height = 1.25cm
Hence the height of the triangular cross section is 1.25cm
Answer:
Extraneous Solutions An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation. Example 1: Solve for x, 1 x − 2 + 1 x + 2 = 4 (x − 2) (x + 2).
Answer: 430 rounded so ur answer is 400
Step-by-step explanation:
you do 86 times 5 and you get 430 the you round it to the nearest hundred and you get 400 as ur answer
Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
