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4 years ago

Solve the equation 10x^4-81x^2+164=0 on the real number system

Mathematics

2 answers:

rusak2 [61]4 years ago

6 0

I got -2,2....................

Natasha_Volkova [10]4 years ago

5 0

x = -2, 2, +/- square root of 41/10

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Solve 75=125 (0.8)t^

valentinak56 [21]

Really night what's the problem

7 0

3 years ago

Read 2 more answers

If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a

harkovskaia [24]

Given:

The function is:

$h(x)=x^2-3x+5$

To find:

The value of $h(2x+1)$ .

Solution:

We have,

$h(x)=x^2-3x+5$

Putting $x=2x+1$ , we get

$h(2x+1)=(2x+1)^2-3(2x+1)+5$

$h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5$

$h(2x+1)=4x^2+4x+1-6x-3+5$

On combining like terms, we get

$h(2x+1)=4x^2+(4x-6x)+(1-3+5)$

$h(2x+1)=4x^2-2x+3$

Therefore, the required function is $h(2x+1)=4x^2-2x+3$ .

3 0

3 years ago

Help me please . quick :)

ycow [4]

Answer:

x= 1

QS = 10 cm

QRS = 40cm

Step-by-step explanation:

4x + 1 = 5x

x= 1 cm

QS = 4x + 1 + 5x

= 9x + 1

= 9 + 1

= 10cm

QRS perimeter

QS + RQ + RS but ( RQ = RS)

= 10 + 15 + 15

= 40cm

3 0

3 years ago

Work out the size of one of the exterior angles

hodyreva [135]

Given Information :-

⠀

A polygon with 10 sides ( Decagon )

⠀

To Find :-

⠀

The value of one of the exterior angles

⠀

Formula Used :-

⠀

$\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star$

⠀

Solution :-

⠀

Putting the given values, we get,

⠀

$\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\$