What is the value of x in the diagram
1 answer:
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Answer:
Since we want to satisfy both at the same time, "x" must be equal or greater than 6.
Step-by-step explanation:
This product is formed by two square roots, since this mathematical operator can only be defined for positive values and zero, the number inside the root must be always greater or equal to 0, on both roots. Therefore:
and
Since we want to satisfy both at the same time, "x" must be equal or greater than 6.
I dont know if you wanted the steps but:
x^2-4x-6=0
plug it into the equation:
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x^2-4/3x+1/3 x=1 , x= 1/3
2x^2-3x+1=0 x=1 , x=1/2
6x^2+12x=-5
add the 5 to both sides
6x²+12x+5=0 plug the problem into the equation
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