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const2013 [10]
2 years ago
12

The first one is exponential form

Mathematics
1 answer:
WITCHER [35]2 years ago
7 0

Answer:

i believe the first one should be 20 5 since its supposed to be in expanded form but i dont know the second one sorry hope you do good

Step-by-step explanation:

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Which of the following illustrates the truth value of the given statements?
Ierofanga [76]

Answer:

FT\rightarrow T

Step-by-step explanation:

If p and q are two statements, then you can use the following table to find the value of p\vee q:

\begin{array}{ccccc}p&|&q&|&p\vee q\\ \\T&|&T&|&T\\T&|&F&|&T\\F&|&T&|&T\\F&|&F&|&F\end{array}

If

p: 7 is an even number  - is false, because 7 is not an even number (F)

q: 3 is the square root of 9 - true, because 3 is the square root of 9 (T),

then according to the above table, p\vee q is true.

Correct option

FT\rightarrow T

6 0
3 years ago
. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person
bulgar [2K]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

5 0
3 years ago
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