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Allisa [31]
3 years ago
15

Need some help with this one.

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

C. 3 cans

Step-by-step explanation:

9 1/9 times 3 is 27.33 and if one can cover 10 square meters then that means you'll need 3 cans.

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Solve for x given the lines are parallel.<br> (7x - 8)<br> 62°
QveST [7]

Answer:

The answer is 0 ✌

Step-by-step explanation:

70 - 8 =62°

3 0
2 years ago
What is the slope for the line PERPENDICULAR to the line shown in the graph?
Levart [38]
The answer is B.
Because the slope= 3x.. and to find the perpendicular line, you need to flip the variable to a fraction and make it negative.
4 0
2 years ago
Can someone plz help me with this answer is not A I’m not understanding it plz help
STatiana [176]
I think it’s C. 136 ft squared
8 0
3 years ago
What is 6.685 rounded to the nearest hundredths place
loris [4]

Answer:

6.69

Step-by-step explanation:

The hundredths place is two decimal places to the right. This lands you at 8, so you must look at the number after it to determine whether you round up or down. So you look at 5, which rounds the 8 up to 9. Therefore, it is 6.69

7 0
3 years ago
Read 2 more answers
You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o
anyanavicka [17]

Answer:

x =\dfrac{45 \sqrt{6}}{ 2}

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}

In order to estimate the point along the shore, x meters from B, the runner should  stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

=\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0

-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0

\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}

\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}

squaring both sides; we get

\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}

\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}

By cross multiplying; we get

49x^2 = 25(54^2+x^2)

49x^2 = 25 \times 54^2+ 25x^2

49x^2-25x^2 = 25 \times 54^2

24x^2 = 25 \times 54^2

x^2 = \dfrac{25 \times 54^2}{24}

x =\sqrt{ \dfrac{25 \times 54^2}{24}}

x =\dfrac{5 \times 54}{\sqrt{24}}

x =\dfrac{270}{\sqrt{4 \times 6}}

x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}

x =\dfrac{45 \sqrt{6}}{ 2}

8 0
3 years ago
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