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skelet666 [1.2K]

3 years ago

10

1. Sheena and her friends want to form a team to play recreational soccer. They want a combination of males and females for the

soccer team. They want to have no more than 7 players on their team.
Part A: Write an inequality to represent the situation. Part B: Graph the inequality and shade the area where the possible solutions would
lie. Part C: What is the difference between the ordered pairs that fall on the line and
the ones that fall in the unshaded area?
Part D: Determine whether these combinations of males, m, and females, f, can be
present.

1 answer:

Vikki [24]3 years ago

8 0

Thx hdhdndnndjdfjfjfh

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Factor completely:<br> x^2-x^2-3.5(x+y)

kkurt [141]

Answer:

− 3.5 ( x + y )

Hope this helps

Step-by-step explanation:

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3 years ago

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a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1

Virty [35]

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

A plane that travels a distance $r$ , in kilometers, with a bearing of $\theta$ sexagesimal degrees can be represented in standard position by means of the following expression:

$\vec r = r\cdot (\sin\theta, \cos \theta)$ (1)

We can obtain the resulting vector ( $\vec R$ ) by the principle of superposition:

$\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]$ (2)

If we know that $r_{1} = 5\,km$ , $\theta_{1} = 0^{\circ}$ , $r_{2} = 6\,km$ , $\theta_{2} = 60^{\circ}$ , $r_{3} = 4\,km$ and $\theta_{3} = 120^{\circ}$ , then the resulting vector is:

$\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})$

$\vec R = (5\sqrt{3}, 6) \,[km]$

The magnitude of the resultant is found by Pythagorean theorem:

$\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}$

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:

$\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)$ (3)

If we know that $R_{x} = 5\sqrt{3}\,km$ and $R_{y} = 6\,km$ , then the magnitude and the bearing of the resultant is:

$\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}$

$\|\vec R\| \approx 10.536\,km$

$\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)$

$\theta_{R} \approx 34.715^{\circ}$

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

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3 years ago

Fred bought 4 liters of liquid laundry detergent 3250 mL of fabric softener and 2.5 L of bleach which date that is true

Colt1911 [192]

The complete question in the attached figure

we know that

<span>Fred bought
</span><span>4 liters of liquid laundry detergent
</span><span>3250 mL of fabric softener------------> 3250/1000-------> 3.25 liters
</span><span>2.5 L of bleach-----------> 2.5 liters

then
</span><span>statements

4a. Fred bought 75 milliliters more fabric softener than bleach
</span>3.25-2.5-------> 0.75 liters--------> 750 mi
the statement is false

<span>4b. Fred brought 1.75 liters more laundry detergent than bleach
4-2.5---------> 1.5 liters
</span>the statement is false

4c. Fred brought 750 milliliters more fabric softener than bleach. <span>
3.25-2.5-------> 0.75 liters-------> 750 ml
</span>the statement is true

4d. Fred brought 150 milliliters more laundry detergent than bleach.
4-2.5--------> 1.5 liters---------> 1500 ml
the statement is false

<span>4e. Fred bought 0.75 liters more laundry detergent than fabric softener.
</span>4-3.25--------> 0.75 liters
the statement is true

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4 years ago

Write an expression for the model. Find the sum.

MakcuM [25]

C. 2 + (–3); –1 is the answer

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DanielleElmas [232]

Answer:

heptagon

Step-by-step explanation:

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