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3 years ago

33 points | dont guess please | no links

Mathematics

1 answer:

Furkat [3]3 years ago

8 0

Answer:

Joe mama

Step-by-step explanation:

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15. • Solve the simultaneous equations

tamaranim1 [39]

Answer:
B. 1 and -2
Explanation:
First, add up the equations:
x-x+3y+y=4
4y=4
y=1
Now, plug y into any of the original equations above and solve for x:
-x+1=3
-x=2
x=-2
Therefore, the answer is B. 1 and -2

5 0

3 years ago

Umm pls help me ik how to do it but not sure on this specific one

Lapatulllka [165]

9514 1404 393

Answer:

-8, +9

Step-by-step explanation:

You need factors of (6)(-12) = -72 that have a sum of +1.

From your knowledge of multiplication tables, you know that 72 = 8·9. Then -72 = (-8)(9), and those two factors have a sum of +1.

6x^2 +x -12

= 6x^2 +9x -8x -12

= 3x(2x +3) -4(2x +3)

= (3x -4)(2x +3)

8 0

3 years ago

PLEASEE HELPP QUICK!!! QUESTIONS IN THE PICTURESS

Setler [38]

9. sensitive noses, big ears, and long tail.
10. ferns, yeasts, hydras, and amoebas

8 0

2 years ago

Read 2 more answers

What is the equation of the quadratic graph with a focus of (6, 0) and a directrix of y = −10 ?

Mademuasel [1]

Answer:

$(x-6)^{2}=20(y+5)^{2}$

Step-by-step explanation:

The standard for for the equation of a parabola is $(x-h)^{2}=4p(y-k)$

The focus is given as $(h, k+p)$

The directrix is given by $y=k-p$

Comparing focus given as $(6,0)$ to formula of focus $(h,k+p)$ , we see that $h=6$ and $k+p=0$
Comparing directrix given as $y=-10$ to formula of directrix $y=k-p$ , we can write $k-p=-10$

We can use the two system of equations [ $k+p=0$ and $k-p=-10$ ] to solve for $k$ and $p$ .

Adding the two equations gives us:

$2k=-10\\k=\frac{-10}{2}\\k=-5$

Using this value of $k$ , we can find $p$ by plugging this value in either equation. Let's put it in Equation 1. We have:

$k-p=-10\\-5-p=-10\\-5+10=p\\p=5$

Now, that we know $h=6$ , $k=-5$ , and $p=5$ , we can plug these values in the standard form equation to figure out the parabola's equation. Doing so and rearranging gives us: