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nadezda [96]
3 years ago
10

Help with 3 short questions

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0
1. mortal
2. plague
3. annihilate
4. pioneer
quester [9]3 years ago
4 0
Sorry I have no idea
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M is between points C and Q. CM=17 and CQ=21. What is MQ?
katrin2010 [14]
Sometimes it helps to draw it out...

     (17)
C_______M_________Q
|___________________|
             21

therefore, CM + MQ = CQ
17 + MQ = 21
MQ = 21 - 17
MQ = 4 <===
8 0
3 years ago
Read 2 more answers
Write a function t(I) that determines the number of
forsale [732]

Using the table, we will see that the function is:

t(l) = 3*l

<h3>How to write the function?</h3>

Here we only have a table to work with, so we need to use that.

In the table, we can see the pairs:

  • t(1) = 3
  • t(2) = 6
  • t(3) = 9
  • t(4) = 12

So, in each new level, we just add 3 more toothpicks. Even more, we can see that the number of toothpicks is 3 times the value of l (the level) for all the cases in the table. So this is a linear function.

From that we can conclude that the function will be:

t(l) = 3*l

If you want to learn more about linear functions, you can read:

brainly.com/question/4025726

6 0
2 years ago
1.1<br>Solve the following equations:<br>1.1.1 (x+5)(x-3)=33​
schepotkina [342]

Step-by-step explanation:

x²-3x +5x -15=33

x²-3x+5x=33+15

x²-3x+5x=48

x²+2x=48

divide both sides by 2

x²+x =24

x²= 24

x= ✓24

dunno from here

8 0
3 years ago
Figure this out please Asap.
weeeeeb [17]

If the polygons are similar then the sides are in proportion.

\dfrac{32}{24}=\dfrac{32:8}{24:8}=\dfrac{4}{3}

Therefore we have the equations:

\dfrac{x-1}{6}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(x-1)=(4)(6)\\\\3x-3=24\qquad\text{add 3 to both sides}\\\\3x=27\qquad\text{divide both sides by 3}\\\\\boxed{x=9}


\dfrac{y+1}{21}=\dfrac{4}{3}\qquad\text{cross multiply}\\\\3(y+1)=(21)(4)\\\\3y+3=84\qquad\text{subtract 3 from both sides}\\\\3y=81\qquad\text{divide both sides by 3}\\\\\boxed{y=27}

6 0
3 years ago
H(-4), h(0), h(4), h(8)
DIA [1.3K]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The first two x-values, -4 and 0, fall in the first part of the function definition.

There is no function definition for x = 4, as the second part only applies for x > 4.

The last x-value, 8, falls in the second part of the function definition.

The function is evaluated by putting the x-value where x is in the expression and doing the arithmetic. For example, ...

  h(-4) = -(-4+1)^2 +7 = -(-3)^2 +7 = -9 +7 = -2

  h(0) = 6

  h(4) = undefined

  h(8) = -8/3

6 0
3 years ago
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