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GaryK [48]
2 years ago
6

Find the value of f (x) F(x) = 2 x f(4) = ......... A. 8 B. -6 C. 10

Mathematics
1 answer:
Alexandra [31]2 years ago
6 0

Answer:

F(4)=8

Step-by-step explanation:

F(x)=2(x)

F(4)

Replace x with 4

F(4)=2(4)

Multiply

F(4)=8

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An equation with more than one variable is called a "literal Equation"
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Studentka2010 [4]

Answer:

word form: One hundred three million seven hundred twenty seven thousand four hundred and ninety five.

expanded form: 100,000,000+3,000,000+700,000+20,000+7,000+400+90+5.

5 0
2 years ago
How many percent is 10 3/20?
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Is that what you were asking?
6 0
3 years ago
Solve the system of equations. 8x – 3y = 1 –2x + 3y = 11 A. (–1, –3) B. (–1, 3) C. (2, 5) D. (5, 2)
Makovka662 [10]

Answer:

C. (2, 5)

Step-by-step explanation:

Looking at the answer choices, you can see that solving for y will tell you which choice is correct. We can eliminate x from the equations by adding 4 times the second equation to the first:

(8x -3y) +4(-2x +3y) = (1) +4(11) . . . . . adding the equations to eliminate x

9y = 45 . . . simplified; next we divide by 9

y = 5 . . . . . matches choice C

_____

Check

8(2) -3(5) = 16 -15 = 1

-2(2) +3(5) = -4 +15 = 11 . . . . the answer checks OK in both equations

4 0
3 years ago
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
3 years ago
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