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3 years ago

15

Water guns are on sale this week. If

1 answer:

GrogVix [38]3 years ago

6 0

Answer:

$6.43

Step-by-step explanation:

8.50 times 0.30=2.55

8.50-2.55=5.95

5.95 times 0.08=0.476

0.476+5.95=6.426 rounded would be $6.43

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

15 crackers weigh 69 grams. how many kilograms is this?

Marrrta [24]

Answer:

$0.069\ kg$

Step-by-step explanation:

we know that

1 kg=1,000 g

so

using proportion

Find out how many kilograms are 69 grams

Let

x -----> the weight in kg

$\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg$

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3 years ago

If Nancy needs 3/1/4 cups of oatmeal,how many 1/4 cups of oatmeal will she use

PIT_PIT [208]

The answer is 12 1/4. how I got my answer.

Their are 4 quarters to a whole, so that means all I have to do is multiply 4×3=12, then add 1/4+12= 12 1/4.

I hope this helps!

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2 years ago

An objects speed can be modeled with the equation s=24(1.06)^t where s represents its speed in miles per hour and t represents t

4vir4ik [10]

$s = 24(1.06)^{t} 
$

24 is the numerical coefficient

1.06 is the base of the power with exponent t

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3 years ago

What are the common factors of 35 and 60?

Ksivusya [100]

I think it is 5 !!!!!!!!!!!!!!

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3 years ago