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alekssr [168]
3 years ago
11

The specific heat of ethanol (C2H5OH) is 2.46 J/g ° C. What is the heat capacity of 1.00 kg of ethanol?

Chemistry
1 answer:
inessss [21]3 years ago
7 0

Answer:

The total heat required is 4088.6 J

Explanation:

We have three processes which involve heat absorption. We have to calculate the heat of each process and then to calculate the total heat.

1- liquid ethanol is heated from 25ºC (298 K) to the boiling point 78.5ºc (351.5 K). We use specifi heat of liquid ethanol to calculate the heat absorbed in this part:

H1= m x Sh x ΔT

H1= m x Sh x (Tfinal - Tinitial)

H1= 3.95 g x 2.45 J/g.K x (351.5 K -298 K)

H1= 517.7 JExplanation:

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How much thermal energy is in 100 grams of water at 50 degrees Celsius
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when the thermal energy is the energy contained within a system that is responsible for its temperature.  

and when the thermal energy  is can be determined by this formula:

q = M * C *ΔT

when q  is the thermal energy

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and C is the specific heat capacity of water = 4.18 joules/gram.°C

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How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

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