The decrease in velocity is called deceleration or negative acceleration.
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Answer:
0.038 g of reactant
Explanation:
Data given:
Heat release for each gram of reactant consumption = 36.2 kJ/g
mass of reactant that release 1360 J of heat = ?
Solution:
As 36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J
As we know
1 KJ = 1000 J
So
36.2 kJ = 36.2 x 1000 = 36200 J
So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release
Apply unity formula
36200 J of heat release ≅ 1 gram of reactant
1360 J of heat release ≅ X gram of reactant
Do cross multiplication
X gram of reactant = 1 g x 1360 J / 36200 J
X gram of reactant = 0.038 g
So 0.038 g of reactant will produce 1360 J of heat.
Answer:
No, just because carbon did not react with water, does not mean it wouldn't react with a different compound.
Explanation:
It is common knowledge that carbon is not in group 18, because it is found in all living compounds, and this means it must be reactive with many compounds. We know that water is not very reactive, but it is a good solvent. Meaning that many compounds can dissolve in water, but not chemically react with it. Carbon however is not very soluble because it does not create dipoles or hydrogen bonds. This means it will not show any change when in the presence of water, but if combined with oxygen, can form carbon dioxide.
1426.58 J and 340.90 calories heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C.
Explanation:
Data given:
mass = 28.4 gram
initial temperature = -23 degrees
final temperature = 1degress
change in temperature ΔT = Tfinal - Tinitial
ΔT = 1 -(-23)
ΔT = 24 degrees
specific heat capacity of ice cube c = 2.093 J/g C
Formula used:
q = mc ΔT
putting the values in the equation:
q= 28.4 x 2.093 x 24
= 1426.58 J
ENERGY IN CALORIES:
340.90 calories is the energy is required in the process.
Explanation:
Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.
Mass of titanium = 90 g
Moles of titanium = 
Total number of atoms of titanium ,
Mass of aluminum = 6 g
Moles of aluminium = 
Total number of atoms of aluminium,
Mass of vanadium = 4 g
Moles of vanadium= 
Total number of atoms of vanadium
Total number of atoms in an alloy = 
Atomic percentage:
Atomic percentage of titanium:
:
Atomic percentage of Aluminium:
:
Atomic percentage of vanadium
:
