Answer:
The neutrons have no charge
Explanation:
im not sure about the second part. good luck
Answer:
119.7 mL.
Explanation:
- From the general law of ideal gases:
<em>PV = nRT.</em>
where, P is the pressure of the gas.
V is the volume of the container.
n is the no. of moles of the gas.
R is the general gas constant.
T is the temperature of the gas (K).
- For the same no. of moles of the gas at two different (P, V, and T):
<em>P₁V₁/T₁ = P₂V₂/T₂.</em>
- P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.
- P₂ = 1.0 atm = 760.0 mmHg (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).
<em>∴ V₂ = (P₁V₁T₂)/(T₁P₂) </em>= (100.0 mmHg)(1000.0 mL)(273.0 K)/(296 K)(760.0 mmHg) = 121.4 <em>mL.</em>
Answer:
7... simalair: made of more than 2 things DIffernt: elemants are made of atoms.
Explanation:
The molarity of the solutions are as follows:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- solutions A and C are mixed together have a lower molarity than B
- solution F and D will have the same molarity
- Volume of water required to be evaporated is 8.3 mL
<h3>What is molarity of a solution?</h3>
The molarity of a solution is the amount in moles of a substance present in a given volume of solution.
From the image of the solution given:
- solution B has the highest molarity
- solutions A, D and F have the same molarity
- when solutions A and C are mixed, the resulting solution have a lower molarity than B
- solution F and D will have the same molarity after 75 mL and 50 mL of water are added to each respectively
- the molarity of B is 12/50 = 4/16.7. Volume of water required to be evaporated = 25 - 16.7 = 8.3 mL
Therefore, the molarity of the solutions depends on the moles of substance present per given volume of solution.
Learn more about molarity at: brainly.com/question/24305514
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Answer:
elements on the left-hand side of the periodic table such as sodium and magnesium prefer to lose electrons to form a cation because this requires less energy to obtain a stable octet, and vice-versa for the right-hand side of the periodic table e.g. fluorine. However, using this reasoning I am not sure why all transition metals tend to lose electrons rather than gain them.