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Firdavs [7]
3 years ago
6

Solve the problem 8 + [(8 × 5) – 10] = ? A. 46 B. 38 C. 58 D. 30

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

For this case, we must resolve the following expression:

8 + [(8 * 5) -10] =

We solve the multiplication within the parenthesis, to eliminate it:

8+ [40-10] =

As a second step, we solve the subtraction:

8 + 30 =

Finally, we add:

38

So, 8 + [(8 * 5) -10] = 38

Answer:

Option B


Vsevolod [243]3 years ago
4 0

Answer:

The answer is A. 38

Step-by-step explanation:

8 + [(8 x 5) - 10] =

8 + (40 - 10) =

8 + 30 = 38

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Jenny is doing a survey on why children like chocolates. Which survey question would she use?
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3 years ago
How many radians are in one degree, accurate to three decimal places?
qaws [65]
Now, if you recall, there are 180° in π radians, now, so how many radians in 1°?

\bf \begin{array}{ccll}
de grees&radians\\
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180&\pi \\
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3 0
4 years ago
Explain and I’ll mark as brainliest too also worth 20 points
USPshnik [31]

Answer:

x = 3

Step-by-step explanation:

The equation is,

16 = 5x+1

Subtract 1 from both sides,

16-1 = 5x

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7 0
3 years ago
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Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
4 years ago
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