The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.
Armed with the above rules, we can split up the summation into simple terms:
=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196
Answer:
Dilation
Step-by-step explanation:
A dilation changes the size of a figure by enlarging the figure of making the figure smaller. The sides will be proportional and the angles will be congruent making the figures similar.
Option D. 96 is the correct answer.
Explanation:
Let the higher grade be = x
Let the lower grade be = y
As given, The difference of the two grades is 16
or 
.... (1)
The sum of one-eighth of the higher grade and one-half of the lower grade is 52.
... (2)
Putting the value of x=16+y in equation (2)
As x=16+y
x=16+80 = 96
Hence, higher grade is 96.
So... let's say the amounts invested were "a" at 6% and "b" at 7.5%.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus
a + b = 5000and the interest yielded was 337.50, thus
0.06a + 0.075b = 337.50thus
solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.
Answer: 33.3%
Step-by-step explanation:
First find the difference between the players in try-outs over the years.
= 90 - 75
= 25
Then use this difference to find the percent increase:
= Difference / Players last years * 100%
= 25 / 75 * 100%
= 33.3%
