Answer:
66
Step-by-step explanation:
Answer:
Step-by-step explanation:
f(x)=-4(x-2)²+3
put x-2=0
axis of symmetry is x=2
g(x)=-2(x²+8x)+15
=-2(x²+8x+4²-4²)+15
=-2(x+4)²+32+15
=-2(x+4)²+47
put x+4=0
axis of symmetry is x=-4
h(x) is minimum at x=1
axis of symmetry is x=1
Answer:
Part A: 25% of 50 = 12.5
Part B: 25% of 60 = 15
Part C: 50% of 60 = 30
Part D: 75% of 60 = 45
Part E: 75% of 30 = 22.5
Part F: 100% of 22.5 = 22.5
Part G: 10% of 22.5 = 2.25
Part H: 50% of 45.7 = 22.85
Step-by-step explanation:
To find - Do you know the answer to
Part A: 25% of 50 =
Part B: 25% of 60 =
Part C: 50% of 60 =
Part D: 75% of 60 =
Part E: 75% of 30 =
Part F: 100% of 22.5 =
Part G: 10% of 22.5 =
Part H: 50% of 45.7 =
Proof -
Part A :
25% of 50 =
=
= 12.5
⇒25% of 50 = 12.5
Part B :
25% of 60 =
=
= 15
⇒25% of 60 = 15
Part C :
50% of 60 =
=
= 30
⇒50% of 60 = 30
Part D :
75% of 60 =
=
= 45
⇒75% of 60 = 45
Part E :
75% of 30 =
=
= 22.5
⇒75% of 30 = 22.5
Part F :
100% of 22.5 =
= 22.5
⇒ 100% of 22.5 = 22.5
Part G :
10% of 22.5 =
= 2.25
⇒ 10% of 22.5 = 2.25
Part H :
50% of 45.7 =
=
= 22.85
⇒50% of 45.7 = 22.85
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ =
≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM =
≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ