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KonstantinChe [14]
3 years ago
10

An auto repair shop charged a customer $496 to repair a car. The bill listed $96 for parts and the remainder for labor. If the c

ost of labor is $40 per hour, how many hours of labor did it take to repair the car?
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
It took 10 hours of labor to repair the car
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I need the answer and if you would please explain step by step
emmasim [6.3K]

Answer:

x=17

Step-by-step explanation:

well the triangles are congruent so that equation has to equal 61, so set it equal to 61, once you do that subtract 10 with 61 giving you 51, then divide 3 with 51 and you get 17

3x + 10 = 61 \\ 3x = 51 \\ x = 17

3 0
3 years ago
What are the outputs of the function below?
chubhunter [2.5K]

Your output would be your g(x)-values, your input your x-values.

So that means your answer is C. 6, 2, -3, 4.

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

4 0
4 years ago
1/2(8x−20)=2(x+6)<br> what is x?
Tomtit [17]

Answer:

X=11...............

7 0
3 years ago
Which expression shows 2x² + 18 factored completely
Lerok [7]

Answer:

2(x^2+9)

Step-by-step explanation:

2x^2 +18

Factor out a 2

2(x^2+9)

3 0
3 years ago
Please help!!!!! ASAP!!!
nika2105 [10]
That's just the distance between 2 points
the distance between (x1,y1) and (x2,y2) is
D= \sqrt{(x2-x1)^2+(y2-y1)^2}

we can find the distance between S and Q or P and R

S and Q is (0,0) and (a,b)

D= \sqrt{(a-0)^2+(b-0)^2}
D= \sqrt{a^2+b^2}

distance between P and R is between(0,b) and (a,0)
D= \sqrt{(a-0)^2+(0-b)^2}
D= \sqrt{(a)^2+(-b)^2}
D= \sqrt{a^2+b^2}

\sqrt{a^2+b^2} = \sqrt{a^2+b^2}
so the lengths of diagonals are congruent
7 0
4 years ago
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