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Andreyy89
2 years ago
7

Choose the answer that best represents the situation described below. George is climbing a mountain. He knows that the higher th

e mountain, the more time the climb will take.
A. The time to climb the mountain is a function of climbing speed.
B. The height of the mountain is a function of climbing speed.
C. The time to climb in the function of its height.
Mathematics
1 answer:
alex41 [277]2 years ago
3 0
It’s c the time to climb in the function of its height
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Solve system by elimination -9x - y =-19 <br> 5x + y = 15
vredina [299]

Answer:

(1, 10 )

Step-by-step explanation:

Given the 2 equations

- 9x - y = - 19 → (1)

5x + y = 15 → (2)

Adding the 2 equations term by term will eliminate the y- term

- 4x + 0 = - 4

- 4x = - 4 ( divide both sides by - 4 )

x = 1

Substitute x = 1 into either of the 2 equations and solve for y

Substituting into (2)

5(1) + y = 15

5 + y = 15 ( subtract 5 from both sides )

y = 10

solution is (1, 10 )

6 0
2 years ago
Need 78 pieces of wood 29 cm long. Boards are 6 m long. How many boards are needed?
Wittaler [7]

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3 years ago
Select the decimal that is equivalent to 45/54
lina2011 [118]

Answer:

.83

Step-by-step explanation:

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3 years ago
A positive integer is 1010 more than 2727 times another. their product is 1211712117. find the two integers.
Goshia [24]
1010 + 2727x = y
x*y = 1211712117
x*(1010 + 2727x) = 1211712117
2727x^2 + 1010x - 1211712117 = 0

Here's the nasty part.
In order for this to work, the square root of the quadratic formula must come back with an integer. In fact sqrt (b^2 - 4ac) comes back with
3635568.29 something. which is not a whole number. Either there is an error in the givens or something, but this question is never going to do what you think it will do.
4 0
3 years ago
which is the rationalized form of the expression the square root of x divided by the square root of x +the square root of 7
Ilya [14]

Answer:

I assume your goal is to rationalize the denominator -

So you need to multiply the denominator by its conjugate.

So we have:

\frac{\sqrt{x} }{\sqrt{x}-\sqrt{7} } *\frac{\sqrt{x} +\sqrt{7} }{\sqrt{x} +\sqrt{7}}

->

\frac{x-\sqrt{7}\sqrt{x} }{x-7}

gg

8 0
3 years ago
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