From the information presented in the movie, what can you

What volume of 1.25 M sodium hydroxide (NaOH) solution can be prepared using 60.0 g of sodium hydroxide? (The mass of one mole o

nataly862011 [7]

Answer:

The answer is

Explanation:

Since the concentration , mass and molar mass of NaOH has been given we use the formula

<h3> $C = \frac{m}{M \times v}$ </h3>

To find the volume

where

C is the concentration

m is the mass

M is the molar mass

v is the volume

Making volume the subject we have

<h3> $v = \frac{m}{C \times M}$ </h3>

From the question

C = 1.25 M

m = 60 g

M = 40.0 g/mol

Substitute the values into the above formula and solve for the volume

We have

<h3> $v = \frac{60}{1.25 \times 40} \\ v = \frac{60}{50} \\ v = \frac{6}{5}$ </h3>

We have the final answer as

<h3>Volume = 1.20 L</h3>

Hope this helps you

8 0

3 years ago

Estimate the surface-to-volume ratio of a C60 fullerene by treating the molecule as a hollow sphere and using 77pm for the atomi

AleksAgata [21]

Answer:

The surface-to-volume ratio of a C-60 fullerene is 3:77.

Explanation:

Surface area of sphere = $S=4\pi r^2$

Volume of the sphere = $V=\frac{4}{3}\pi r^3$

where : r = radius of the sphere

Radius of the C-60 fullerene sphere = r = 77 pm

Surface area of the C-60 fullerene = $S=4\pi (77 pm)^2$ ...[1]

Volume area of the C-60 fullerene = $V=\frac{4}{3}\pi (77 pm)^3$ ..[2]

Dividing [1] by [2]:

$\frac{S}{V}=\frac{4\pi (77 pm)^2}{\frac{4}{3}\pi (77 pm)^3}$

$=\frac{3}{77}$

The surface-to-volume ratio of a C-60 fullerene is 3:77.

7 0

3 years ago

Bonds payable issued with collateral are called _______ bonds.

NeX [460]

The answer to your question is letter D. Secured.

8 0

3 years ago

A welding torch produces a flame by burning acetylene fuel in the presence of oxygen. This flame is used to melt a metal. Which

NISA [10]

Answer:

chemical energy into thermal energy

Explanation:

The reaction taking place is as follows

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O + Heat

In this reaction bonds present in acetylene is broken and new bond present in water and carbon dioxide are formed . In the whole process of bond breaking and bond formation , there is net loss of energy and that energy is released as heat energy .

Thus we can say that in the whole process , chemical energy is converted into heat energy .

5 0

3 years ago

What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?

yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃ + 3C → 4Fe + 3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5 . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83 . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0

3 years ago