__Fe + ___ Cl2 --> __

If 0.500L solution weighs 596g and contains 90.0g of oxalis acid, the concentration can be expressed as ?M, or ?(m/m)%, or ?(m/v

irinina [24]

Answer : The concentration can be expressed as, 1.99 M, or 15.1(m/m)%, or 18(m/v)%

Solution : Given,

Volume of solution = 0.5 L = 500 ml (1 L = 1000 ml)

Mass of solution = 596 g

Mass of oxalic acid, (solute) = 90 g

Molar mass of oxalic acid = 90.03 g/mole

First we have to calculate the concentration in terms of M(molarity).

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

Formula used : $M=\frac{w_{solute}}{M_{solute}\times V_s}$

where,

M = molarity of solution

$w_{solute}$ = mass of solute(oxalic acid)

$M_{solute}$ = molar mass of solute(oxalic acid)

$V_s$ = volume of solution(in liters)

Now put all the given values in this formula, we get

$M=\frac{90g}{90.03g/mole\times 0.5L}=1.99mole/L=1.99M$

Now we have to calculate the concentration in terms of (m/m)%

(m/m)% : It is defined as the mass of solute present in mass of solution in grams.

Formula used : $(m/m)\%=\frac{w_{solute}}{w_s}\times 100$

where,

$w_s$ = mass of solution

$(m/m)\%=\frac{90g}{596g}\times 100=15.1%$

Now we have to calculate the concentration in terms of (m/v)%

(m/v)% : It is defined as the mass of solute present in one milliliter of solution.

Formula used : $(m/v)\%=\frac{w_{solute}}{V_s}\times 100$

where,

$w_s$ = mass of solution

$(m/m)\%=\frac{90g}{500ml}\times 100=18%$

8 0

3 years ago

When aqueous solutions of K3PO4 and Ba(NO3)2 are combined, Ba3(PO4)2 precipitates. Calculate the mass, in grams, of the Ba3(PO4)

Firdavs [7]

Answer:

Mass of Ba₃(PO₄)₂ = 0.0361 g

Explanation:

Given data:

Volume of Ba(NO₃)₂ = 1.2 mL (1.2 × 10⁻³ L )

Molarity of Ba(NO₃)₂ = 0.152 M

Volume of K₃PO₄ = 4.2 mL (4.2 × 10⁻³ L)

Molarity of K₃PO₄ = 0.604 M

Mass of Ba₃(PO₄)₂ produced = ?

Solution:

Chemical equation:

3Ba(NO₃)₂ + 2K₃PO₄ → Ba₃(PO₄)₂ + 6KNO₃

Number of moles of Ba(NO₃)₂ = Molarity × Volume in litter

Number of moles of Ba(NO₃)₂ = 0.152 M × 1.2 × 10⁻³ L

Number of moles of Ba(NO₃)₂ = 0.182 × 10⁻³ mol

Number of moles of K₃PO₄ = Molarity × Volume in litter

Number of moles of K₃PO₄ = 0.604 M × 4.2 × 10⁻³ L

Number of moles of K₃PO₄ = 2.537 × 10⁻³ mol

Now we will compare the moles of Ba₃(PO₄)₂ with K₃PO₄ and Ba(NO₃)₂ .

Ba(NO₃)₂ : Ba₃(PO₄)₂

3 : 1

0.182 × 10⁻³ : 1/3 ×0.182 × 10⁻³ = 0.060 × 10⁻³ mol

K₃PO₄ : Ba₃(PO₄)₂

2 : 1

2.537 × 10⁻³ : 1/2 × 2.537 × 10⁻³= 1.269 × 10⁻³ mol

The number of moles of Ba₃(PO₄)₂ produced by Ba(NO₃)₂ are less it will limiting reactant.

Mass of Ba₃(PO₄)₂ = moles × molar mass

Mass of Ba₃(PO₄)₂ = 0.060 × 10⁻³ mol × 601.93 g/mol

Mass of Ba₃(PO₄)₂ = 36.12 × 10⁻³ g

Mass of Ba₃(PO₄)₂ = 0.0361 g

6 0

4 years ago

The _______________ react with the _______________ elements to form different compounds like lithium fluoride (LiF) and sodium c

likoan [24]

Answer: Alkali metals, halogens, noble gases

Explanation:

Ionic compounds are made of ions- charges. In LiF and NaCl, the first element has a +1 and the second element has a charge of -1. Elements that are +1 are alkali metals and elements that are -1 are halogens. Noble gases have full octets in their outermost valence shell, and since they're full it's so stable so it doesn't react with anything.

8 0

3 years ago

What contribution to atomic theory resulted from Albert Einstein's work?

lions [1.4K]

Answer:

a new model of the atom that describe electrons as being in a cloud

Explanation:

5 0

3 years ago

A

Ilia_Sergeevich [38]

both A and B are physical properties

5 0

3 years ago

Read 2 more answers

__Fe + ___ Cl2 --> ___FeCl3

Fe + _ Cl2 --> ___FeCl3