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Softa [21]
3 years ago
14

Which physical property does the inventor need to consider when choosing a

Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

A.

............

Explanation:

Ductility

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stellarik [79]

Answer: 1.824

Explanation: facts

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If a student's unknown is a colorless liquid and its boiling point was measured to be about 78°C
maks197457 [2]
It might be ethanol. :)
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How much 2.0 M phenylmagnesium chloride solution is needed if adding 2.9 mmol of Grignard reagent to a reaction? Your answer sho
Vladimir [108]

Answer:

1,45 mL

Explanation:

The Grignard reaction is a very important organometallic chemical reaction where the Grignard reagent ( alkyl, vinyl, or aryl-magnesium halides) acts as nucleophile in order to the formation of Carbon-Carbon bonds.

In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:

2,9 mmol × \frac{1mL}{2,0mM} = <em>1,45 mL</em>

<em></em>

I hope it helps!

3 0
3 years ago
After fertilization, female cones become very:<br> sticky<br> light<br> O hard
S_A_V [24]

Answer:

light

Explanation:

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8 0
3 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

5 0
3 years ago
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