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viktelen [127]
1 year ago
13

A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day give

n b.i.d.
Chemistry
1 answer:
bixtya [17]1 year ago
7 0

The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

<h3>What is the amount of Amoxicillin dose given to the child?</h3>

The amount of  Amoxicillin  dose given to the child is calculated as follows;

amount of Amoxicillin dose = weight of the child x dosage prescribed

<h3>What is the weight of the child in pounds (lb) </h3>

The weight of the child in pounds (lb) is calculated as follows;

1 lb = 0.453592 kg

85.4 lb = ?

= 85.4 x 0.453592 kg

= 38.74 kg

amount of Amoxicillin dose = 38.74 kg x 45 mg/kg

amount of Amoxicillin dose = 1,743.3 mg

Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

Learn more about amount of dose here: brainly.com/question/11185154

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The complete question is below:

A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.

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Initial                          0.27             0.49              0.0

Change                      -x                  -2x                 x

Equilibrium               0.27 - x         0.49 -2x          x

We can now say that the concentration of  CH_3OH_{(g)} at equilibrium is x;

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K_C = \frac{[CH_3OH]}{[CO][H_2]^2}

K_C = \frac{(0.11)}{(0.16)[(0.27)^2}

K_C = 9.4307

K_C = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0
3 years ago
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