Answer:
a) Mass of solution is 16,605 milli grams.
b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
Explanation:
Mass by mass percentage of calcium chloride solution, wt% = 12.0%
Density of the solution = d = 1.107 g/mL
a) Volume of the solution , V= 15.0 mL
Mass of the solution = m
Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)
b) Mass of the solution = m
Volume of the solution = V = 431.3 mL
Mass of calcium chloride = x
w% = 12.0%
57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) Moles of calcium chloride = 
V = Volume of the solution in Liters
n = 0.5161 mole
V = 431.3 mL = 0.4313 L
1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
I’m pretty sure it’s A it’s been awhile
Answer:
In the given figure, There are two atoms -
- Sodium ( Na )
- Chlorine ( Cl )
sodium has one electron in valence shell and to get noble gas configuration ( stability ) it need to donate the outer most electron.
whereas,
chlorine has 7 electrons in valence shell and to get noble gas configuration ( stability ) it need to get one more electron.
in this condition Na ( sodium ) donates it's outermost electron to Cl ( chlorine ) and both became stable.
but now sodium has more number of protons than the electrons hence it get positive (+) charge and chlorine has more electrons than the protons hence it get negative (-) charge
so, they get stick to each other by strong electrostatic force acting on the charged atoms and forms a salt " NaCl " ( sodium chloride ) .
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
The answer to this would be false.
