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Alexxandr [17]
3 years ago
11

Write a letter to your friend describing your feelings after you left the school

Chemistry
1 answer:
fredd [130]3 years ago
8 0
Dear friend,
How are you doing? I finally switched to my new school and it's been so hard adjusting. But I know I have a new chance at making new friends and memories. Also, I can learn new things, like interacting with new people and how to keep my anxiety low. I really miss us hanging out and how much we'd laugh and get in trouble at class. But i really hope to see you soon & that it hasn't gone terribly wrong for you since i left.
your friend,
name
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A student was asked to prepare exactly 250 mL of a 0.500 M aqueous potassium hydroxide solution. What mass of potassium hydroxid
atroni [7]

Answer:

Option 5 → 7.01 g

Explanation:

Molarity . volume (L) = Moles

This can help us to determine the moles of KOH that are in the solution.

We convert the volume from mL to L → 250 mL . 1L / 1000mL = 0.250 L

0.5 mol /L . 0.250L = 0.125 moles of KOH

Now, we only have to convert the moles to mass, by the molar mass:

Moles . molar mass = mass →  0.125 mol . 56.1 g/mol = 7.01 g

4 0
3 years ago
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What is the largest number that can be added to 6.022x10^23 without changing its displayed value?
Juli2301 [7.4K]
<span>The Avogadro constant, named after the scientist Amedeo Avogadro, is the number of constituent particles, usually atoms or molecules, that are contained in the amount of substance given by one mole. The answer, in this case, would be 0.0004999...*10^23 = (10^19)*(4.999... [any finite number of 9s]).</span>
3 0
3 years ago
Pls help this isn’t hard I’m just not sure about the answer this is also Science ATTENTION
fgiga [73]
The answer is probably c i guess
6 0
3 years ago
A sample of unknown hydrate, AC-XH20, has a mass of 1.000 g before heating and a
KIM [24]

Answer:

The water of crystallization for the formula of the unknown  hydrate is 2.

Explanation:

Mass of an unknown hydrate = 1.000 g

Molar mass of hydrate = 195.5 g/mol

MOles of unknown hydrate =\frac{1.000 g}{195.5 g/mol}=0.00512 mol

Mass of hydrate after heating = 0.781 g

Mass of water lost due to heating = x

1.000 g = 0.781 g + x\\x = 1.000 g - 0.781 g = 0.219 g

Moles of water lost =\frac{0.219 g}{18.01528 g/mol}=0.0122 mol

AC.xH_2O+Heat\rightarrow AC+xH_2O

1 Mole of hydrate has x moles of water and 0.00512 moles of hydrate has 0.0122 moles of water then we can write:

\frac{1 }{x}=\frac{0.00512 }{0.0122 }\\x\approx 2

The water of crystallization for the formula of the unknown  hydrate is 2.

7 0
3 years ago
What is the process of using one or more of your five senses to measure or collect data?
sveta [45]

Answer:

B no observation pls mark me branilest

7 0
3 years ago
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