If $1 is 75 yen and there is $25, multiply 25*75 to get the total amount of yen. 25*75 = 1875 yen was what he had to pay
The answer is negative, it’s negative because the dots are going down instead of up
The answer is (B).
Draw any triangle ABC. Reflect this triangle across the line AB, creating triangle A'B'C' for which A'=A and B'=B. By definition of a reflection, sides B'C and B'C' are congruent. In addition, sides A'C and A'C' are congruent. The quadrilateral CA'C'B' has two pairs of consecutive sides that are congruent and no congruent opposite sides. By definition, this is a kite.
Answer:
= 11/3
Step-by-step explanation:
1. COMBINE MULTIPLIED TERMS INTO A SINGLE FRACTION
- 7/3 (3x-2)= -21
-7 (3x-2) = -21
-----------------------
3
2. DISTRIBUTE
-7( 3x- 2) ➗ 3 =-21
3. MULTIPLY ALL TERMS BY THE SAME VALUE TO ELIMINATE FRACTION DENOMINATORS
-21x + 14 ➗ 3 = 3 (-21)
4. CANCEL MULTIPLIED TERMS THAT ARE IN THE DENOMINATOR
3 ( -21x + 14) ➗ 3 (-21)
5. MULIPLY THE NUMBERS
-21x + 14 = 3(-21)
6. SUBTRACT 14 FROM BOTH SIDES OF THE EQUATION
-21x + 14 = -63
7. SIMPLIFY
-21x = - 77
8. DIVIDE BOTH SIDES OF THE EQUATION BY THE SAME TERM
-21x/-21 = -77/-21
9. SIMPLIFY
x = 11/3
First, we have to make sure that the number of columns in the first matrix is equal to the number of rows in the second matrix.
![\left[\begin{array}{cc}1&-3&2&0\\\end{array}\right] * \left[\begin{array}{ccc}2&3&4\\1&2&3\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-3%262%260%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%2A%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%264%5C%5C1%262%263%5Cend%7Barray%7D%5Cright%5D%20)
Since this is true, we can continue to solve the problem.
To multiply two matrices, multiply each row element in the first matrix by each column element in the second matrix. For example:
1*2 = 2
-3*1=-3
Then we add them to get our new matrix element.
-3+2=
-1Then we move to the next column of the second matrix.
1*3=3
-3*2=-6
-6+3=
-3Then the final column of the second matrix.
1*4=4
-3*3=-9
-9+4=-5
Our matrix so far:
![\left[\begin{array}{ccc}-1&-3&-5\\x&x&x\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-3%26-5%5C%5Cx%26x%26x%5Cend%7Barray%7D%5Cright%5D%20)
We do the same for the bottom row of the first matrix.
<em>First Column</em>
2*2=4
0*1=0
4+0=
4<em>Second Column
</em>2*3=6
0*2=0
6+0=
6
<em>Third Column</em>
2*4=8
0*3=0
8+0=
8Our final matrix is:
![\left[\begin{array}{ccc}-1&-3&-5\\4&6&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-3%26-5%5C%5C4%266%268%5Cend%7Barray%7D%5Cright%5D)
:)