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Rina8888 [55]
2 years ago
10

Help me out important!!!!!!!

Mathematics
1 answer:
Oliga [24]2 years ago
3 0

Answer:

This might help:

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Given m < TUV = 78, find m < WUV
meriva

Answer:

m∠WUV = 23°

Step-by-step explanation:

m∠TUW and m∠WUV must add up to m∠TUV

Step 1: Set up equation

m∠TUW + m∠WUV = m∠TUV

8x + 7 + 4x - 1 = 78

Step 2: Solve for <em>x</em>

12x + 6 = 78

12x = 72

x = 6

Step 3: Find m∠WUV

m∠WUV = 4x - 1

m∠WUV = 4(6) - 1

m∠WUV = 24 - 1

m∠WUV = 23°

7 0
3 years ago
A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange. Let B =
Oduvanchick [21]

Answer: \frac{11}{75}

Step-by-step explanation:

R is the event of getting a red jelly bean. 22 out of the 150 jelly beans are red. That means it is a \frac{22}{150} chance of getting a red jelly bean.

Simplified that is \frac{11}{75}

8 0
3 years ago
there are 11 days until Richards's concert. Susie's concert is 7 days after Richard's. How many days are there until Susie's con
matrenka [14]
There are 11 days until Richards's concert.
Susie's concert is 7 days after Richard's.

so Susie's concert: 11+7=18
answer
D. 11+7=18
8 0
3 years ago
Please help me due on Friday
barxatty [35]

Answer:

The correct answer is B (The universe was hotter previously than it is now

3 0
2 years ago
Read 2 more answers
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
3 years ago
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