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zaharov [31]
3 years ago
11

For a closed cylinder with radius r ⁢ cm and height h ⁢ cm, find the dimensions giving the minimum surface area, given that the

volume is 40 cm3.
Mathematics
1 answer:
elena55 [62]3 years ago
3 0

<span>we know the surface area of the two ends of the closed cylinder is: 2 (r</span>2) .

<span>The surface are of the side of the cylinder is h (2r)</span>

<span>So the total surface area is: 2 ( r</span>2<span>) + h (2 r )</span>

<span>The volume of the cylinder is r</span>2 h = 40 cm3

now solve this last equation for h:

<span>so, h = 40 / (*r</span>2)

Substitute the value for h into the expression for the total surface area:

<span>2 ( r</span>2<span>) + (40 / ( r</span>2<span>)) (2 r )</span>

Now Simplify the above expression we get:

<span>2 ( r</span>2) + (80 / r)

Now take the derivative:

<span>4  r - 80 r </span>-2

Set it equal to zero and solve for r:

<span>4  r - 80 r </span>-2 = 0

Divide by 4:

*r - 20 r -2 = 0

Multiply by r2 we get:

 r3 - 20 = 0

 r3 = 20

r3 = 20/

Hence,

<span>r = (20 / )</span>(1/3)

r  1.8534 cm

<span>Substitute this value for r into h = 40 / ( r</span>2) and evaluate h:

<span>h = 40 / *(1.8534)</span>2

    h  3.7067

<span> </span>

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