The answer would be 3.5 to that calculation
Answer:
- 32,283 years old
- 31,718 years old
Step-by-step explanation:
If h is the half-life of the radioactive substance, then the proportion remaining after t years is ...
k = (1/2)^(t/h)
We can find the value of t using logarithms:
log(k) = (t/h)·log(1/2)
t = h·log(k)/log(1/2)
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a) For k = 2% and h = 5720 years, we have ...
t = 5720·log(.02)/log(.5) ≈ 5720·5.64386
t ≈ 32,283 . . . . years old
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b) For k = 2% and h = 5620 years, we have ...
t ≈ 5620·5.64386 ≈ 31,718 . . . . years old
_____
Note the proportionality of age to half-life. Once we found the multiplier corresponding to 2% remaining, we can use that for any estimate of the half-life.
Circumfernce=diameter times pi
given that we should use 3.14 for pi
and diameter is 11.9
circumfernce=11.9 times 3.14=37.366
the circumference is 37.366cm
That's the simplest lololol
Answer: 14 students will be in each group
84 divided by 6 = 14
