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3 years ago

(3x + 3x²) + (2x² + 2x)?

Mathematics

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

=5x2+5x

Step-by-step explanation:

Let's simplify step-by-step.

3x+3x2+2x2+2x

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We can't see any given circle. The general form for a circle centered at the origin with radius r is

$x^2 + y^2 = r^2$

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3 years ago

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The function y = -15 +2100 can be used to model the height, y, of a parachute jumper x seconds after she jumps from an airplane.

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Did you mean to put a x after -15?

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2 years ago

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The following list shows the colours of a random selection of sweets.

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Categorical or Continuous.

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2 years ago

What is the slope of the line that passes through the points (-4, -2)(−4,−2) and (-4, -22) ?(−4,−22)? Write your answer in simpl

Anestetic [448]

The line is vertical, so the slope is infinite

Step-by-step explanation:

Given two points with coordinates $(x_1, y_1)$ and $(x_2,y_2)$ , the slope of the line passing through the two points is given by the equation

$m=\frac{y_2-y_1}{x_2-x_1}$

In this problem, the coordinates of the two points are:

$(x_1,y_1)=(-4,-2)$

and

$(x_2,y_2)=(-4,-22)$

which means:

$x_1=-4\\y_1=-2\\x_2=-4\\y_2=-22$

Substituting all these values into the equation of m, we find the slope of the line:

$m=\frac{-22-(-2)}{-4-(-4)}=\frac{-20}{0}=\infty$

The slope is infinite: this is because the line is vertical.

Learn more about slope of a line:

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3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

2 years ago

(3x + 3x²) + (2x² + 2x)?​

(3x + 3x²) + (2x² + 2x)?