Evaluate find the degree of a polynomial (y³-2)(y²+11)

Find the Volume of this Octagonal Pyramid. "B" represents the Area of the octagon base.

Dominik [7]

Answer:

7.06 x 10^(-7) ft 3

Step-by-step explanation:

We have the formula to calculate the volume of an octagonal Pyraamid as following:

+) Volume of octagonal pyramid = 1/3 * Area of the base * Height

As given, the base of the pyramid is an octagon with area equal to 15mm2

=> Area of the base = 15 mm2

The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.

=> Height = 4mm

So we have:

Volume of octagonal pyramid = 1/3 * Area of the base * Height

= 1/3 * 15 * 4 = 20 mm3

As: 1 mm3 = 3.53 x 10^(-8) ft 3

=> 20 mm3 = 7.06x10^(-7) ft 3

So the volume of the pyramid is : 7.06 x 10^(-7) ft 3

6 0

3 years ago

Ryan works at at the donut shop where he makes $10.25 per hour . He also works part time at the school bookstore where he makes

SCORPION-xisa [38]

Answer:

6 hours

Step-by-step explanation:

Let

x----> the number of hours worked at the donut shop

y----> the number of hours worked at the school bookstore

we know that

x+y=20

x=20-y -----> equation A

10.25x+8.75y=196 -----> equation B

Substitute equation A in equation B and solve for y

10.25(20-y)+8.75y=196

205-10.25y+8.75y=196

10.25y-8.75y=205-196

1.5y=9

y=6 hours at the school bookstore

7 0

3 years ago

Can someone please help me on number 16-ABC

melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

Part a) Is x = 0 a solution to both inequalities

FOR -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

Part b) Is x = 4 a solution to both inequalities

FOR -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

solving -2x < 10

$-2x\:$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)>10\left(-1\right)$

Simplify

$2x>-10$

Divide both sides by 2

$\frac{2x}{2}>\frac{-10}{2}$

$x>-5$

$-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}$

solving -6 < -2x

-6 < -2x

switch sides

$-2x>-6$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)$

Simplify

$2x$

Divide both sides by 2

$\frac{2x}{2}$

$x$

$-6$

Thus, the two intervals:

$\left(-\infty \:,\:3\right)$

$\left(-5,\:\infty \:\right)$

The intersection of these two intervals would be the solution to both inequalities.

$\left(-\infty \:,\:3\right)$ and $\left(-5,\:\infty \:\right)$

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0

3 years ago

Which answer is the equivalent of sin x? A. tan y B. cos x C. tan x D. cos y

trapecia [35]

Sin x = cos y

Angles x and y a complementary.
Sine and cosine are co-functions.
sin x = cos (90 - x)
sin x = cos y

3 0

3 years ago

Read 2 more answers

Given that 1/f = 1/u + 1/v , express u in terms of v and f

JulijaS [17]

Answer:

u = fv/(v - f)

Step-by-step explanation:

1/f = 1/u + 1/v

1/u = 1/f - 1/v = v/fv - f/fv = (v-f)/fv

1/u = (v-f)/fv

u = fv/(v - f)

5 0

3 years ago

Evaluate find the degree of a polynomial (y³-2)(y²+11)​

Evaluate find the degree of a polynomial (y³-2)(y²+11)