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Andreas93 [3]
4 years ago
6

Theres 2 here, pleaseeee help

Mathematics
1 answer:
True [87]4 years ago
4 0
With the first one, you just plug the numbers inside the parentheses into f(x). Therefore:
f(-2)=40
f(-1)=18
f(0)=8
f(1)=10
f(2)=24

For the second one, you look at the table and find where x=1. The number there is 24, so therefore, f(1)=24
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So what makes a graph point line equivalent like this, does it go through the origin or is it just that its a straight line
Trava [24]

Answer:

I'm pretty sure that it's just a single straight line that makes it equivalent. I could be wrong tho

hope this helped

8 0
3 years ago
How do I get the answer
EleoNora [17]
\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
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sec(\theta)=\cfrac{1}{cos(\theta)}\\\\
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\cfrac{1\underline{-sin(\theta)}+1\underline{+sin(\theta)}}{[1-sin(\theta)][1+sin(\theta)]}\implies 
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\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
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\cfrac{2}{1^2-sin^2(\theta)}\implies \cfrac{2}{1-sin^2(\theta)}\implies \cfrac{2}{cos^2(\theta)}
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\cfrac{2}{1}\cdot \cfrac{1^2}{cos^2(\theta)}\implies 2sec^2(\theta)
5 0
3 years ago
Read 2 more answers
Hey, can anyone help me with this? Okay, so in the equation 10 + 3x= -17 . The answer or (x) = -9 because you minus 10 on both s
Delvig [45]

Answer:

You do -17 + -10 inorder to change the operation used because both negatives does not mathematically look nice.

Step-by-step explanation:

To isolate the unknown, we need to move all the numbers on one side of the equal sign and all the unknow variables on one side.

Here we move 10 on the other side by taking away 10 both sides

10 + 3x = -17

-10 -10

then we are left with only 3x on one side and -27 on the other side because -17 - -10 = -27 , in this case it is acknowledge to change the operation from minus to add because the two minus are together, so we say -17 + -10 .

3x = -27

/3 /3

x = -9

6 0
4 years ago
Find the integral, using techniques from this or the previous chapter.<br> ∫x/√16+8x^2 dx.
chubhunter [2.5K]

\displaystyle\int\frac x{\sqrt{16+8x^2}}\,\mathrm dx

Let u=16+8x^2\implies\mathrm du=16x\,\mathrm dx. Then the integral becomes

\displaystyle\frac1{16}\int\frac{\mathrm du}{\sqrt u}\,\mathrm du=\frac18\sqrt u+C

=\dfrac18\sqrt{16+8x^2}+C

6 0
3 years ago
Which expressions are equivalent. Picture Provided. NO LINKS! NEED ANSWER ASAP
DIA [1.3K]

Answer:

B) 3^-5 <em>(1 / 243)</em> and D) 2^5 x 6^-5 <em>(</em><em>1</em><em> </em><em>/</em><em> </em><em>2</em><em>4</em><em>3</em><em>)</em>

Step-by-step explanation:

3 to the negative 5th power as a fraction is

1 / 243.

2 to the power of 5 multiplied by 6 to the power of negative 5 also equals 1 / 243.

Both expressions are equivalent to 2^5 / 6^5 because they equal the same thing (1 / 243).

3 0
3 years ago
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