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mina [271]
3 years ago
11

Select the correct answer Giving brainliest

Chemistry
2 answers:
Alinara [238K]3 years ago
3 0

Answer:

i also need help with this lmk yo

Explanation:

brilliants [131]3 years ago
3 0

Answer:

I think the answer is d let me know if it right

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These are the photos for part A
Alla [95]

Answer:

Explanation:

For part C, this should be what the graph looks like.

The reactants should have higher energy that the products so that it can release energy. Recall the reaction is N2 + 3H2 => 2NH3 + energy, making it exothermic. Apparently, you are supposed to adjust the energy diagram on the simulation so that 20% of the reactants become the products.  

6 0
3 years ago
Decide which model best represents the relationship between Earth and the sun and what causes day and night. Explain your choice
bearhunter [10]

Answer:

table lamp

Explanation:

lol odrk

6 0
3 years ago
5. A 180 mL disinfectant solution contains 85 mL of isopropyl alcohol. Determine the V/V
lyudmila [28]

The % V/V concentration of a 180-mL disinfectant solution containing 85 mL of isopropyl alcohol is 47 % V/V.

<h3>What is the % V/V concentration?</h3>

It refers to the milliliters of solute for every 100 milliliters of solution.

We have 180 mL of a disinfectant solution that contains 85 mL of isopropyl alcohol (solute).

The % V/V concentration of this solution is:

% V/V = (mL solute/mL solution) × 100% =

% V/V = (85 mL/180 mL) × 100% = 47% V/V

Learn more about % V/V here: brainly.com/question/17055828

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7 0
2 years ago
In a piston, the volume was noticed to be 2.50 liters at 25°C. If the temperature rose to 55°C, what is the new volume?
GrogVix [38]

Answer:

The new volume is 2.75L

Explanation:

This is another case of Charles Gay Lussac law, where the volume varies directly proportional to T°, if the pressure keeps on constant.

V₁ / T₁  =  V₂ / T₂

25°C + 273 = 298K

55°C + 273 = 328K

2.5L / 298K = V₂ / 328K

(2.5L / 298K) . 328K = V₂

2.75L = V₂

8 0
4 years ago
Read 2 more answers
a 1.750-g sample of mercury metal ws combined with 1.394 g of bromine. Determine the empirical formula of the mercury bromide th
Airida [17]

Answer:

HgBr₂.

Explanation:

  • To determine the empirical formula of the mercury bromide that is produced, we should calculate the no. of moles of Hg (1.750 g) and Br (1.394 g) used to prepare the mercury bromide.

no. of moles of Hg = mass/atomic mass = (1.75 g)/(200.59 g/mol) =  0.00872 mol.

no. of moles of Br = mass/atomic mass = (1.394 g)/(79.904 g/mol) =  0.01744 mol.

  • We divide by the lowest no. of moles (0.00872) to get the mole ratio:

The mole ratio of (Br: Hg) is: (2: 1).

<em>So, the empirical formula is: HgBr₂.</em>

<em></em>

6 0
3 years ago
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