Question

If anyone could help?

Answer 1

Answer:

$y=\frac{5}{7}x$ and $y=\frac{7}{9}x$

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In $y=\frac{5}{7}x$ when x=3, y=15/4≈2.14

In $y=\frac{3}{5}x$ when x=3, y=1.8

In $y=\frac{7}{9}x$ when x=3, y≈2.33

In $y=\frac{7}{11}x$ when x=3, y≈1.90

We can observe that in two cases, $y=\frac{5}{7}x$ and $y=\frac{7}{9}x$, y is greater than 2.