. Multiplying the denominator by
gives

Subtracting this from the numerator gives a remainder of

. Multiplying the denominator by
gives

and subtracting this from the previous remainder gives a new remainder of

This last remainder is exactly the same as the denominator, so
divides through it exactly and leaves us with 1.
What we showed here is that



and this last expression is the quotient.
To verify this solution, we can simply multiply this by the original denominator:



which matches the original numerator.
Answer:
- <u>The correct statement is the first one: </u><u><em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean</em></u><em> </em>
<em />
Explanation:
To calculate how many<em> standard deviations</em> a particular value in a group is from the mean, you can use the z-score:

Where:
is the number of standard deviations the value of x is from the mean
is the mean
is the standard deviation
Substitute in the formula:

Which means that <em>the number of blue-eyed students in Mr. Garcia's class is 2 standard deviations</em> above the mean.
Above the mean is the same that to the right of the mean, because the in the normal standard probability graph the central value is Z = 0 (the z-score of the mean value is 0), the positive values are to the right of the central value, and the negative values are to the left of the central value.
Therefore, the correct statement is the first one: <em>The number of blue-eyed students in Mr. Garcia's class is 2 standard deviations to the right of the mean, </em>
Y=a(x-h)^2+k
is what vertex form look like. (h,k) is your vertex so in this problem your vertex would be (60,200)
Answer:
y=7
Step-by-step explanation:
-6y= -27-15
-6y= -42
y=7
Across the y axis. This question becomes easier if you graph it out in your head. Let's say the bank is at (2,2). Because the grocery store has an opposite x coordinate, the bank would be at (-2,2). If you look at this in your head, they are not even on different sides of the x axis, and therefore must be reflected across the y axis.