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2 years ago

If a skateboard cost a store owner $55.20 to purchase, what price must the

Mathematics

1 answer:

Kryger [21]2 years ago

4 0

Answer:

69 dollars

Step-by-step explanation:

Thats the Answer

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A researcher believes that headaches can be relieved by drinking water flavored by

olganol [36]

Answer: A. Experimental Study

4 0

3 years ago

Which equation shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation

Andrej [43]

Answer:

$5x= 15$

Step-by-step explanation:

Given

$3x - 5 = -2x +10$

Required

Write the variables and constants on different sides

$3x - 5 = -2x +10$

Add 2x to both sides

$2x + 3x - 5 =2x -2x +10$

$5x - 5 =10$

Add 5 to both sides

$5x - 5 + 5 = 10 + 5$

$5x= 10 + 5$

$5x= 15$

Hence, the equation is

$5x= 15$

Solving further [divide both sides by 5]

$x = 3$

3 0

3 years ago

(1 point) (a) Find the point Q that is a distance 0.1 from the point P=(6,6) in the direction of v=⟨−1,1⟩. Give five decimal pla

natima [27]

Answer:

following are the solution to the given points:

Step-by-step explanation:

In point a:

$\vec{v} = -\vec{1 i} +\vec{1j}\\\\|\vec{v}| = \sqrt{-1^2+1^2}$

$=\sqrt{1+1}\\\\=\sqrt{2}$

calculating unit vector:

$\frac{\vec{v}}{|\vec{v}|} = \frac{-1i+1j}{\sqrt{2}}$

the point Q is at a distance h from P(6,6) Here, h=0.1

$a=-6+O.1 \times \frac{-1}{\sqrt{2}}\\\\= 5.92928 \\\\b= 6+O.1 \times \frac{-1}{\sqrt{2}} \\\\= 6.07071$

the value of Q= (5.92928 ,6.07071 )

In point b:

Calculating the directional derivative of $f (x, y) = \sqrt{x+3y}$ at P in the direction of $\vec{v}$

$f_{PQ} (P) =\fracx{f(Q)-f(P)}{h}\\\\$

$=\frac{f(5.92928 ,6.07071)-f(6,6)}{0.1}\\\\=\frac{\sqrt{(5.92928+ 3 \times 6.07071)}-\sqrt{(6+ 3\times 6)}}{0.1}\\\\= \frac{0.197651557}{0.1}\\\\= 1.97651557$

$\vec{v} = 1.97651557$

In point C:

Computing the directional derivative using the partial derivatives of f.

$f_x(x,y)= \frac{1}{2 \sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{2 \sqrt{22}}\\\\f_x(x,y)= \frac{1}{\sqrt{x+3y}}\\\\ f_x (6,6)= \frac{1}{\sqrt{22}}\\\\f_{(PQ)}(P)= (f_x \vec{i} + f_y \vec{j}) \cdot \frac{\vec{v}}{|\vec{v}|}\\\\= (\frac{1}{2 \sqrt{22}}\vec{i} + \frac{1}{\sqrt{22}} \vec{j}) \cdot \frac{-1}{\sqrt{2}}\vec{i} + \frac{1}{\sqrt{2}} \vec{j}$