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jenyasd209 [6]
3 years ago
10

A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th

e year, and passes 80 percent of the remaining quizzes successfully, what is the percent of all successful quizzes for the entire year?
Plz help thanks!
Mathematics
1 answer:
NikAS [45]3 years ago
4 0

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

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Do  15  and  40  have any common factors ?
Let's see . . .

The factors of  15  are  1,  3,  <em>5</em>, and  15 .
The factors of  40  are  1,  2,  4,<em>  5</em>,  8,  10,  20, and  40 .

Ah hah !  Do you see that ' <em>5</em> ' on both lists ?  That's a common factor.

So  15/40  is NOT in lowest terms.

Divide the numerator and denominator both by  5 :

       15 / 40  =<em>  3 / 8</em>

3  and  8  don't have any common factor except ' 1 '. 
So  3/8  is the same number as  15/40, but in lowest terms.


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