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jenyasd209 [6]
3 years ago
10

A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th

e year, and passes 80 percent of the remaining quizzes successfully, what is the percent of all successful quizzes for the entire year?
Plz help thanks!
Mathematics
1 answer:
NikAS [45]3 years ago
4 0

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

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Is x a solution to 80<-9x+8
saveliy_v [14]

Answers: x

1. Switch sides

-9x+8>80

2. Subtract by 8 from both sides of equation.

-9x+8-8>80-8

3. Simplify.

-9x>72

4. Multiply by -1 from both sides of equation. (it's should be the reverse inequality).

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5. Simplify.

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6. Then you had to divide by 9 from both sides of equation.

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7. Simplify.

\frac{9x}{9}=x

8. Divide by the numbers.

\frac{9}{9}=1

=x

\frac{-72}{9}=-8

9. Divide by the numbers.

\frac{72}{9}=8

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x

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