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MArishka [77]
3 years ago
15

The school collected money for sweatshirts. If 75 students bought sweatshirts and the total cost was $1,260, how much did each s

tudent pay?
Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

16.08

Step-by-step explanation:

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#18 how would u not multiplying to find which is grater
Snowcat [4.5K]
In the first product the numerator of the fraction is greater than the denominator, therefore the fraction is greater than 1. On the other hand in the second product the numerator of the fraction is smaller than the denominator, therefore the fraction is smaller than one. That means the first product is greater than the second one.
3 0
3 years ago
Read 2 more answers
What is 23% of 200? Please help
Effectus [21]

Answer:

46

Step-by-step explanation: .23 (200) = 46

6 0
3 years ago
Read 2 more answers
An actor invests some money at 7%, and $48000 and more than twotimes the amount of 9%. The total annual interest earned from the
forsale [732]

Answer:

At 7% $54,000

At 9% $156,000

Step-by-step explanation:

Let x be the amount invested at 7%, Then 2x + 48000 will be the amount invested at 9%

We know that:

7% = 0.07 & 9% = 0.09

So we can write the interest equation as follows:

0.07x + 0.09 (2x + 48000) = 17820

0.07x + 0.18x + 4320 = 17820

0.25x + 4320 = 17820

Subtracting 4320 from both sides of the equation we get:

0.25x = 17820 - 4320

0.25x = 13500

Dividing both sides of the equation by 0.25 we get:

x = 13500 / 0.25

x = $54,000 invested at 7%

&

2 x 54000 + 48000

= $156,000 invested at 9%

Hence the amount invested at 7% is $54,000.

& the amount invested at 9% is $156,000.

5 0
3 years ago
Any help please and thank you
tatyana61 [14]

Answer:

n=6

j=15

u=7.6

Step-by-step explanation:

Given TACBRD=MYPXEF

we find that the ratio is 1 : 2.5 and we solve from here

6 0
3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
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