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2 years ago

Which is the solution set of a for -3(-x a) 7<5 when x=-1 ?

Mathematics

1 answer:

masha68 [24]2 years ago

6 0

Answer: CAN I DO YOU PLS

Step-by-step explanation:

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Find all the powers of 3 that are in the range 3 through 1000

Ksivusya [100]

So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729

and 3^7 is 2187 which is excluded

8 0

3 years ago

Please help ill mark brainliest

liraira [26]

Answer:

it's 11

Step-by-step explanation:

8 0

2 years ago

Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif

xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0

3 years ago

The average cost when producing x items is found by dividing the cost function, C(x), by the number of items, x. When is the ave

Mazyrski [523]

Answer will have to be ( B )

7 0

2 years ago

Read 2 more answers

Please answer this (photo below)

lozanna [386]

Answer:

Please see attached image for the graph

Step-by-step explanation:

To graph the elevation versus time, we start by plotting the first point at time zero (when the climb begins) when Zane is 20 meters below the edge (-20 meters). This corresponds to the point (0, -20).

One second later (1 in the horizontal axis), Zane has moved up 4 meters, now reaching -16 meters. This is the point (1, -16) on the graph.

One second later at time 2 seconds, he is another 4 meters up which corresponds to the point (2, -12) on the graph.

you can go on like this plotting more points on the graph.

Please see the attached image that illustrates this and shows the appropriate line that represents Zane's position versus time (pictured in red)

7 0

3 years ago