Don’t understand this kind of math
Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer: first open your mouth then hold the pear and put it inn your mouth then chew then it will go down your thought
Step-by-step explanation:
Answer:
4.8
Step-by-step explanation:
Um, I'm not sure how to explain, but watch a khan academy video on it
We need to find out how much is worth one yard in both fabrics, so we divide $15.00 by 2 and $37.50 by 5:
$15.00 ÷ 2 = $7.50 per yard
$37.50 ÷ 5 = $7.50 per yard
As both prices per yard are the same, the answer is: <span>Yes, these fabrics have the same unit cost.</span>