Rate of Change:
At 1 mile in 30 seconds.
At 5 miles in 2.5 minutes. 2.5 minutes = 2.5*60 = 150 seconds.
Rate of change = Change in height / Change in time
= (h₂-h₁)/(t₂-t₁)
= (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.
= (1/30) miles per second or 0.0333 miles per second.
To have the answer in miles per minute.
(1/30) miles per second = (1/30) miles/second.
60 seconds = 1minute
1 second = (1/60) minute.
(1/30) miles/second = (1/30) miles/(1/60)minute
= (1/30) *60 miles / minute
= 2 miles per minute.
To find the answer you need to find the square root of e^2 to get e so what you do to one side of the equation you do to the other side of the equation so find the square root of 0.36.
e=positive or negative 0.6
Answer: Sin L =
and CosL=
and Tan L=![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Step-by-Step Explanation:
Since we have given that
Consider, ΔLMN,
LM = 15
MN = 20
NL= 25
![\sin L=\frac{Perpendicular}{Hypotenuse}\\\\\sin L=\frac{20}{25}=\frac{4}{5}](https://tex.z-dn.net/?f=%5Csin%20L%3D%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%5C%5C%5C%5C%5Csin%20L%3D%5Cfrac%7B20%7D%7B25%7D%3D%5Cfrac%7B4%7D%7B5%7D)
And,
![\cos L=\frac{Base}{Hypotenuse}\\\\\cos L=\frac{15}{25}=\frac{3}{5}](https://tex.z-dn.net/?f=%5Ccos%20L%3D%5Cfrac%7BBase%7D%7BHypotenuse%7D%5C%5C%5C%5C%5Ccos%20L%3D%5Cfrac%7B15%7D%7B25%7D%3D%5Cfrac%7B3%7D%7B5%7D)
And,
![\tan L=\frac{Perpendicular}{base}\\\\\tan L=\frac{20}{15}=\frac{4}{3}](https://tex.z-dn.net/?f=%5Ctan%20L%3D%5Cfrac%7BPerpendicular%7D%7Bbase%7D%5C%5C%5C%5C%5Ctan%20L%3D%5Cfrac%7B20%7D%7B15%7D%3D%5Cfrac%7B4%7D%7B3%7D)
Hence,
Sin L =
and CosL=
and Tan L=![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
C = -5
8c-6=2c-36
8c-2c=-36+6
6c=-30
Let’s call the rise X and the span Y
The pitch is the ratio of the rise (X) to half the span (Y)
So the pitch = X/(1/2Y)
Which equals 8 / [(1/2) x 30]
Which equals 8/15